NodeJS + mongoDB查询：承诺/回调

我有三个功能

A-> mongoDb查询，然后调用B，然后console.log（“ test”）

B->设置一些规则并呼叫C

C-> mongoDb查询返回A-> console.log（“ test”）

我在异步/承诺上遇到了麻烦，在很长一段时间后，我发现了一个似乎不太优雅的可行解决方案。（也许是因为我对异步/等待不是很熟悉）我想知道是否有更好/更优雅/更易读的解决方案？

这里是仅包含“有用部分”的代码。 （console.logs应该写1,2,3,4,5,6。）

app.get('/searchWingding', (req,res)=>{
    users.findOneAndUpdate( mongoDBQuery
                                    {returnOriginal : false})
                        .then(async () =>{  
                            //remove unnecessary code for issue
                                console.log(1)                                  
                                await wingdingsExhibitionRule(users,player, allWingdings)
                                console.log(6)
                            })})

async function wingdingsExhibitionRule(users,player, wingdingsList){
        //remove unnecessary code for issue
        console.log(2)                                  
    await changePlayerUnlock(users,player,"wingdingsExhibition")
    console.log(5)                                  
}

async function changePlayerUnlock(users,player,unlockRule){
    //remove unnecessary code for issue
    console.log(3)
const a = users.findOneAndUpdate(mongoDBQuery,
                        {returnOriginal : false})
.then(()=>{                 
                            console.log(4)
                            if(!checkStringInArray(player.unlock,unlockRule)){
                            player.unlock.push(unlockRule)
                            }
                        })
await a
}
```

您正在使用async-await语法和Promise。您的代码可以仅使用async-await语法来编写，如下所示：

app.get('/searchWingding', async (req,res)=> {
      await users.findOneAndUpdate()
      console.log(1)
      await wingdingsExhibitionRule(users,player, allWingdings)
      console.log(6)

async function wingdingsExhibitionRule(users,player, wingdingsList){
     console.log(2)                                  
     await changePlayerUnlock(users,player,"wingdingsExhibition")
     console.log(5)                                  
}

async function changePlayerUnlock(users,player,unlockRule) {
    console.log(3)
    const a = await users.findOneAndUpdate()
    console.log(4)
}

NodeJS + mongoDB查询：承诺/回调

我有三个功能

A-> mongoDb查询，然后调用B，然后console.log（“ test”）

B->设置一些规则并呼叫C

C-> mongoDb查询返回A-> console.log（“ test”）

我在异步/承诺上遇到了麻烦，在很长一段时间后，我发现了一个似乎不太优雅的可行解决方案。（也许是因为我对异步/等待不是很熟悉）我想知道是否有更好/更优雅/更易读的解决方案？

这里是仅包含“有用部分”的代码。 （console.logs应该写1,2,3,4,5,6。）

app.get('/searchWingding', (req,res)=>{
    users.findOneAndUpdate( mongoDBQuery
                                    {returnOriginal : false})
                        .then(async () =>{  
                            //remove unnecessary code for issue
                                console.log(1)                                  
                                await wingdingsExhibitionRule(users,player, allWingdings)
                                console.log(6)
                            })})

async function wingdingsExhibitionRule(users,player, wingdingsList){
        //remove unnecessary code for issue
        console.log(2)                                  
    await changePlayerUnlock(users,player,"wingdingsExhibition")
    console.log(5)                                  
}

async function changePlayerUnlock(users,player,unlockRule){
    //remove unnecessary code for issue
    console.log(3)
const a = users.findOneAndUpdate(mongoDBQuery,
                        {returnOriginal : false})
.then(()=>{                 
                            console.log(4)
                            if(!checkStringInArray(player.unlock,unlockRule)){
                            player.unlock.push(unlockRule)
                            }
                        })
await a
}
```

您正在使用async-await语法和Promise。您的代码可以仅使用async-await语法来编写，如下所示：

app.get('/searchWingding', async (req,res)=> {
      await users.findOneAndUpdate()
      console.log(1)
      await wingdingsExhibitionRule(users,player, allWingdings)
      console.log(6)

async function wingdingsExhibitionRule(users,player, wingdingsList){
     console.log(2)                                  
     await changePlayerUnlock(users,player,"wingdingsExhibition")
     console.log(5)                                  
}

async function changePlayerUnlock(users,player,unlockRule) {
    console.log(3)
    const a = await users.findOneAndUpdate()
    console.log(4)
}