从阵列中获取当天的最低和最高时间
我有这样的对象数组
const timings = [{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "10:00" },
thursday: { from: "05:00", to: "13:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "13:00", to: "14:20" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:40" },
thursday: { from: "11:00", to: "16:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
},
]
我希望输出包含数组中当天的最低和最高时间
例如输出：
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "13:40" },
thursday: { from: "05:00", to: "16:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
}
我想出了一个很长的解决方案，但是它真的很长而且效率不高。
我的解决方案
mondayFrom = timings.map(d => (d.monday && d.monday.from))
mondayTo = timings.map(d => (d.monday && d.monday.to))
tuesdayFrom = timings.map(d => (d.tuesday && d.tuesday.to))
// .... rest of the days
这将生成一个数组，我可以从该数组中找到最小值和最大值，但是我觉得这是一个不好的逻辑。
[如果有更好的方法，请告诉我。谢谢
回答如下：使用reduce使它相当简单
const timings = [{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "10:00" },
thursday: { from: "05:00", to: "13:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "13:00", to: "14:20" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:40" },
thursday: { from: "11:00", to: "16:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
},
]
let result = timings.reduce((a, x) => {
Object.entries(x).forEach(([dow, obj]) => {
if(!a[dow]) {
a[dow] = Object.assign({}, obj);
} else {
a[dow].from = a[dow].from < obj.from ? a[dow].from : obj.from;
a[dow].to = a[dow].to > obj.to ? a[dow].to : obj.to;
}
});
return a;
}, {});
console.log(result);
从阵列中获取当天的最低和最高时间
我有这样的对象数组
const timings = [{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "10:00" },
thursday: { from: "05:00", to: "13:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "13:00", to: "14:20" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:40" },
thursday: { from: "11:00", to: "16:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
},
]
我希望输出包含数组中当天的最低和最高时间
例如输出：
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "13:40" },
thursday: { from: "05:00", to: "16:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
}
我想出了一个很长的解决方案，但是它真的很长而且效率不高。
我的解决方案
mondayFrom = timings.map(d => (d.monday && d.monday.from))
mondayTo = timings.map(d => (d.monday && d.monday.to))
tuesdayFrom = timings.map(d => (d.tuesday && d.tuesday.to))
// .... rest of the days
这将生成一个数组，我可以从该数组中找到最小值和最大值，但是我觉得这是一个不好的逻辑。
[如果有更好的方法，请告诉我。谢谢
回答如下：使用reduce使它相当简单
const timings = [{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "10:00", to: "17:00" },
tuesday: { from: "09:00", to: "10:00" },
thursday: { from: "05:00", to: "13:00" },
friday: { from: "02:00", to: "13:30" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "13:00", to: "14:20" },
tuesday: { from: "11:00", to: "13:00" },
thursday: { from: "11:00", to: "13:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
},
{
monday: { from: "12:00", to: "13:00" },
tuesday: { from: "11:00", to: "13:40" },
thursday: { from: "11:00", to: "16:00" },
friday: { from: "11:00", to: "13:00" },
saturday: { from: "11:00", to: "13:00" },
sunday: {from: "00:00", to: "23:59"}
},
]
let result = timings.reduce((a, x) => {
Object.entries(x).forEach(([dow, obj]) => {
if(!a[dow]) {
a[dow] = Object.assign({}, obj);
} else {
a[dow].from = a[dow].from < obj.from ? a[dow].from : obj.from;
a[dow].to = a[dow].to > obj.to ? a[dow].to : obj.to;
}
});
return a;
}, {});
console.log(result);