如何使用节点js迭代不规则的嵌套json

我正在Nodejs做一个小应用程序，我正在努力尝试循环一个不规则的JSON来打印它的数据。

我的JSON有下一个结构：

{
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
}

我想要做的是打印JSON中包含的所有数据（我想要的东西）：

courses
Java
attendees = 43
...
Anne Baes
hours = 45
experience = 40
completed = false
prevExperience = true

我尝试过：

for(element in data){
    console.log(`element = ${{element}}`);
}

它只打印：

element = [object Object]
element = [object Object]

（这是有道理的，因为json由两个元素组成）

我试过嵌套线：

for(element in data){

这里的问题是有一个不规则的结构，我的意思是，“java”和“python”是相同级别的数据，但同时它们具有不同的（数组和对象）类型的值，并且在“教师”的情况下它们具有相同类型的价值，但它们的价值数量不同。

有人可以帮帮我吗？:(

你可以使用递归和for..in循环来做到这一点

const obj = {
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
};
function print(obj,isArr = false){
  for(let key in obj){
    if(typeof obj[key] === 'object'){
      if(isArr === false) console.log(key)
      print(obj[key],Array.isArray(obj[key]));
    }
    else console.log(`${key} = ${obj[key]}`)
  }
}
print(obj)

如何使用节点js迭代不规则的嵌套json

我正在Nodejs做一个小应用程序，我正在努力尝试循环一个不规则的JSON来打印它的数据。

我的JSON有下一个结构：

{
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
}

我想要做的是打印JSON中包含的所有数据（我想要的东西）：

courses
Java
attendees = 43
...
Anne Baes
hours = 45
experience = 40
completed = false
prevExperience = true

我尝试过：

for(element in data){
    console.log(`element = ${{element}}`);
}

它只打印：

element = [object Object]
element = [object Object]

（这是有道理的，因为json由两个元素组成）

我试过嵌套线：

for(element in data){

这里的问题是有一个不规则的结构，我的意思是，“java”和“python”是相同级别的数据，但同时它们具有不同的（数组和对象）类型的值，并且在“教师”的情况下它们具有相同类型的价值，但它们的价值数量不同。

有人可以帮帮我吗？:(

你可以使用递归和for..in循环来做到这一点

const obj = {
"courses": [
    {
        "java": [
            { "attendees": 43 },
            { "subject": "Crash course" }
        ]
    },
    {
        "python":
        {
            "occurrences": [
                { "attendees": 24 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ,
                { "attendees": 30 },
                { "subject": "another crash course" },
                { "notes": "completed with issues" }
            ]
        }
    }
],
"instructors":[
    {
        "John Doe":[
            { "hours": 20 },
            { "experience": 50 },
            { "completed": true }
        ]
    },
    {
        "Anne Baes": [
            { "hours": 45 },
            { "experience": 40 },
            { "completed": false},
            { "prevExperience": true}
        ]
    }
]
};
function print(obj,isArr = false){
  for(let key in obj){
    if(typeof obj[key] === 'object'){
      if(isArr === false) console.log(key)
      print(obj[key],Array.isArray(obj[key]));
    }
    else console.log(`${key} = ${obj[key]}`)
  }
}
print(obj)